What does [a|b|c] evaluate to in Prolog?
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Published on 2010-06-03T15:00:33Z
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The pipe operator in prolog returns one or more atomic Heads and a Tail list.
?- [a,b,c] = [a,b|[c]].
true.
Nesting multiple pipes in a single match can be done similar to this:
?- [a,b,c] = [a|[b|[c]]].
true.
What does the statement [a|b|c]
infer about a, b and c?
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